IIT JEE , AIEEE Forum - Physics , Mechanics

shinee

a cylindrical vessel containing a liquid od density

, there are two holes in the walls at he heights of h1, h2 respectively such hat the range of he liquid emerging from the vessel is same.the height of the orifise from which the range is maximum is

shubham_sachdeva

let the total height of container of be h

so for h1 height

Ux = (2gh1)^1/2

Sy = h-h1 , Uy = 0

h-h1 = 1/2g.t^2

Sx = range = (2gh1)^1/2 . (2(h-h1)/g)^1/2 = 2 (h1(h-h1))^1/2

similarily for h2

Sx = 2(h2(h-h2))^1/2

as range (or Sx) is equal

so

h1(h-h1) = h2(h-h2)

which gives

h = (h1)^2 - (h2)^2

h1-h2

h = h1+h2

now for max range orrifice should be situated at h/2

= h1+h2

2 ANS.

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