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saurabhgoyal (0)

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an ideal organ pipe resonate at sucessive frequencies of 50 ,150,250HZ etc,(speed of sound=340m/s) find lenght and nature open at both end or closed at one end

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cvramana (639)

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The general mode of vibration of a pipe closed at one end and open at the other end is given by
 
N = (2p + 1) C0 / 4 L          ---------------------(1)
 
Where 2p + 1 is the no. of  harmonic. Since only odd number is possible the given frequencies 50, 150, 250 belong to closed pipe.
 
Therefore
 
L = 340 / 4 (50) = 1.7 m
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