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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: "WAVE MOTION-1"
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prateek.agarwal (307)

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seems simple...but just can't solve it...

    
KAB (1674)

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Let the mass be placed at a distance x from the left end.
 
Let the tension in the left string be T1 and tension in the right string be T2.
 
Now taking moments about the left end,
48x+12*0.2=T2*0.4....(1)  (Since weight of the rod acts at the midpoint of the rod.)
 
Taking moments about right end,
48(0.4-x)+12*0.2=T1*0.4......(2)
 
Also given f=1/2Lroot(T1/m)=2/2Lroot(T2/m)
 
So T1=4T2.....(3)
 
Solve (1),(2) and (3) you will get x=5cm
 
So the mass should be kept at a distance of 5cm from the left end.

ADARSH
NITK Surathkal

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prateek.agarwal (307)

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Olaaa!! Perrrfect answer. 59  [65 rates]

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man...KAB u r so intelligent...rating u,,,
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