Q1 A pointer attached to one prong of a tuning fork just presses against a plate and 30 complete waves were counted by the time the plate fell by 0.1 m.Calculate the frequency of the prong.

Q2 The fundamental frequency of a closed organ pipe is 400 Hz. If a hole be made 10 cm below the open end,



       what will be the fundamental frequency?

Q3 For y= acos(kx)cos(wt), find the shape of graph of:

      a) Change in pressure of the medium at t=0.

      b) Density of the medium at t=T/2.

    SALUTES ASSURED TO ALL CORRECT ANSWERS.

1.  ans is 300 / sqrt.(2)

HOW???

is it correct and dude do rate me

Yes, u are correct. cud u plz tell me how u got the ans?

waiting for the rates as u promised

question is not framed perfectly..



frequency in first case in terms of length of pipe is:



v/4l= (V1)/8







and for second its :  (V2)/6.







If both are same then,, 330/8=(v2)/6;  v2=247.5 m/s

......

1) find the time for which it falls



using s = ut + 1/2 gt^2          ,         u = 0



t = sq rt2 / 10



so frequency = 30 / t

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here is the method

u basically need to find out the time of motion

0.1 = 1/2 g t²

from here u get  t = 0.141 = sqrt (2) x 10^-1

then frequency = 300/ sqrt (2)

3. draw displacement -time graph from given eqn. and shift it by pie/2

  u will get pressure time graph

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Come on goiitians, try it!!!!!!!!!!!!!!!!!!