Q) A wire of density 9000kg/m^3 is stretched between two clamps 1m apart and it's length increases by 0.05cm. Calculate the frequency of the fundamental transverse vibration in the wire.
(Y=9*10^10 N/m^2)
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given density D = 9000kg/m^3 therefore = AD we have Y = stress/strain Y = (T/A)/(dL/L) => T = AYdL/L velocity of transverse wave in wire = v = root (T/) = root ( Y dL / L D) putting values v = root (5000).......u can re-chk my calculation f = v/lambda = nv/2L for fundamental n = 1 f = v/2L = (5000)/2
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236
1
= AD
5000)/2
