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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 18:37:27 IST
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while dealing with problems of newton's laws , a question arises in mind about where to apply T1=T2,T1=2T2? also,which pulley is to be considered?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 18:53:16 IST
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wherever string length is constant u can apply that ,ie for each string u can relate the vel, accn of the objects connected to it.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 22:06:35 IST
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the basic concept it dat tension always act in a dir away from a body. if a mass is hanging from pulley. so for a mass T 'll b acting towards pulley i.e away from it. for pulley it 'll b acting towards mass. so dats how we show the dir away from it. if any doubt ask me. hope u got it.
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do the best &leave the rest. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 22:15:46 IST
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Net Tension in string is constant (if it is mass less and pully is massless and friction less). So if T1 and T2 are tensions in two ends of same string on the pully theT1=T2 The net force acting on a pully is constant.So if a string is supporting a pully with tension T1 and tension in two ends of string on the pully is T2 then T1=2T2
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Nov 2007 13:49:07 IST
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remember that tension is always act in opp. dir. ... T1=T2 when there is only thread and blocks r attached with their ends...
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T1=2T2 when when there is two pulley.. one thread passing throw 1 pulley and one end is tied by a block and another is by other pulley and from this 2nd pulley again two blocks attached with the thread passing throw it..
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if u live to be a hundred
i want to live to be hundred minus 1 day
so i never have to live without u
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Nov 2007 19:03:24 IST
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mostly there is a difference in tensions only when there is a movable pulley..this resuts in one tension being twice of the other.....for fixed pulley, tension is alwaysl equal on both sides of the pulley provided that the string is massless and inextensible....
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