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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jan 2008 00:48:40 IST
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A particle is moving in a straight line under a retardation of av^n+1 where v is the velocity at time t and a is the constant,x is the displacement.Show that if u be the velocity of the particle at t=0 then at=(1/x)(1/v^n-1/u^n)
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23 Jan 2008 02:44:40 IST
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The acceleration is w = -avn+1
dv/dt = -avn+1
u v v-(n+1)dv = -a 0t dt
v-n - u-n = nat
at = (1/n)(v-n - u-n)
I think it should be n in place of x in the problem
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this reply: 5 points
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