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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Feb 2008 15:26:54 IST
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Assume liquid is non-volatile The first picture does not have a lid, but the second one has a lid on the jar. I am not sure of this, cause I have an explanation for both the type of answers. For 'yes',I have : Yes cause the amount of air inside the jar is going to be the same and hence the amount of air pushing on the water surface is the same and thus the same pressure! But for 'no' I have to say that when I am closing the jar I am closing it from the atmosphere and hence the amount of air on top of the column changes, and thus the pressure wont be the same! I sound sort of contradicting cause I havent understood this properly  .Please help me out!
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11 Feb 2008 15:58:16 IST
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no in pic 2 u have an additional vapour pressure acting on the surface of the liquid u can get it like this at any tempareture below freezing point water liquid - water vapour equilibrium exists so some of this water vapour will occupy the space between lid and surface and this exess pressure is what is vapour presssure
u get this in all buks
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11 Feb 2008 16:04:22 IST
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But I have vapour pressure in the first picture too, and the same amount too!
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11 Feb 2008 16:12:11 IST
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2nd system is a closed system but 1st one is an open system so water vapour escapes to the surroundings lowering vapour pressure but in case 2 it is present over there
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11 Feb 2008 16:14:53 IST
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Ok fine one more condition: what if the liquid is non-volatile
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11 Feb 2008 16:15:03 IST
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see hopes:
i feel:
pressure would not be same in both...\
in diagram1 :
PatA = Patm + vapr pr
in diagram 2:
PatA = Pht of air below the lid + vapr prssr
it is so bcoz tumhare lid ki capability hai ki vo patm ko bear kar sakta hai.......
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so, we love all. |
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11 Feb 2008 16:17:26 IST
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Ok, thnx.... I'll just wait for couple of more answers!
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11 Feb 2008 16:22:06 IST
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you dont have to look at the amount of air pushing it, you have to look at the pressure of the air pushing the surface of the liquid... since the pressure of the air above the liquid surface in both cases is the same,the pressure at point A will be same in both cases.
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11 Feb 2008 16:22:13 IST
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@ hopes not volatile liquids also have vapours coz u see any liquid will have a gas phase coz there must be some bonds holding a liquid together these can be broken on application of energy 4get all tis
we are speakin about water ok n tats really volatile even at 1degree celcius ( rate low but still volatile ) @ yuiop read ur answer again see it is this amount of air that will be responsible for ur so called pressure . water vapour also exists my dear so as water vapour is denser than air its effective mass increadses and hence pressure increases . get it ???? ok dude read the topis " VAPOUR PRESSURE " FROM ANY PHYSICAL CHEMISTRY BOOK OR ........
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11 Feb 2008 16:33:47 IST
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hey, thanks. anyway, water vapour is less dense than air(molecular wt. 18), compared to air. whats ur opinion?
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11 Feb 2008 16:39:05 IST
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YA I TOO KNEW SOMEONE WILL POINT THIS OUT COZ MY 2ND PART OF ANS GOES AGAINST MUKULS....
ANS SO U HAV CORRECTED IT AND THANK YOU
IT IS MY FEELING THAT VAPOUR IS MORE DENSER COZ I GET THAT HOT VAPOUR INTO MY NOSE FROM THE HOT WATER DURING BATH SO I FELT IT MUST BE DENSER THAN AIR 4GETIT U CAN LAUGH ABT IT
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