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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jan 2008 21:44:17 IST
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a brick with dimensions 20*10*8 (in cms) has a mass of 5kg.it is lying on longer base.it is then made to lie with length vertical.calculate W.D.: options are 2,3,4,5 J sorry folks but don't know the answer
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there are numerous options besides I.I.T
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15 Jan 2008 21:59:21 IST
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Initially the base is the 20 * 10 surface
Finally the surface on which it stands is the 10 * 8 one
Hence work done in order to make it lie with the longest side vertical is
= [5 * 10 * 6 ] / 100
{Initially height is 8 cm .....later it becomes 20 cm so shift of c.o.m = 6 cm}
= 3 J
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