IIT JEE , AIEEE Forum - Physics , Mechanics

nsv_j89

Two springs A & B(k_A=2k_B) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, that in B is

(a) E/2

(b) 2E

(c) E

(d) E/4.

anshul_2009

We know Energy=1/2 k x^2

For A Energy =E

means E = 1/2 Ka x^2

so in B

E' = 1/2 Kb x^2

but Ka/2=kb

therefore E' = E/2

(A)

RATE ME IF I AM CORRECT

nsv_j89

I am also gitting same ans.,but ans. given in H.C. Verma is (b) 2E

dream

ya answer shud be B

see the force is dame and hence is the displacement

given that 1/2kx^2 = E

for second spring it is going to be
1/2 2kx^2 = 2E

jain108

ya

2E

sboosy

prac_108

yeah d tension in both springs is d same.

so if xtension in spring is x den in spring b it is 2x...

so u get 2E as d ans.

ashish_banga

dream displacement is not same as K is not same