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12 May 2009 23:43:21 IST

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40. Let the potential energy of electron in hydrogen atom in the ground state be regarded as zero.

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40. Let the potential energy of electron in hydrogen atom in the ground state be regarded aszero. Then its potential energy in the first excited state will be(a) 20.4 eV(b) 13.6 eV(c) 3.4 eV(d) 6.8 eV(e) 10.2 eV

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Abishek

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13 May 2009 08:22:19 IST

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Ashwin Menon

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13 May 2009 17:39:56 IST

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No that is wron.

sowmya

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13 May 2009 18:54:52 IST

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ANS: e

Ashwin Menon

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13 May 2009 19:59:42 IST

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No. Answer give is a.Please explain how?

Chris21

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19 May 2009 12:52:48 IST

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ill give 2 proofs..

1st, u assume the lone e is mid between 2 hydrogen nuclei and thats the reason for its 0 potential energy, if it jumps to 1st level..its radius quadruples... BTW H* is the parent nuclei... and the other is supposed to be a test charge..

(H*)_._._._(e)_._._._.(H)...>>>._._._._. corr to 0.53Angstrom

and now

(H)_._._._._._._._(H)_._._._._._._._.(e)

now its potential is

But , for r=0.53A

Chris21

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19 May 2009 12:59:08 IST

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2nd is simpler...wkt PE=2*TE

PE in ground state is 13.6*2 = -27.2ev

PE in 1st excited state is 3.4*2 = -6.8ev

the differnce in potentials is 20.4ev

so if the ground is regarded to be 0

we get the 1st excited to be 20.4ev!

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