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Scorching goIITian

Joined:	31 Oct 2007
Post:	227

1 Feb 2008 11:57:18 IST

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answer it

Engineering Entrance , Medical Entrance , AIPMT , JEE Main , AIIMS , JEE Advanced , Physics , Modern Physics

alpha particle of energy 5Mev is scattered through 180 degrees by a fixed uranium nucleus. the distance of closest approach?

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Purav Master

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Joined: 9 Nov 2006

Posts: 814

3 Feb 2008 01:45:39 IST

Like 2 people liked this

Simply use energy conservation.

KE = PE

5 MeV = 2ke(92e)/r^2

Solve for r. Thats the ans

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