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HYDROGEN ATOM IN ITS GROUND STATE IS EXCITED BY MEANS OF A MONOCHROMATIC RADIATION OF WAVELENGTH 970.6.HOW MANY DIFFERENT TRANSITIONS ARE POSSIBLE IN THE RESULTING EMISSION SPECTRUM? FIND THE LONGEST WAVELENGTH AMONG THESE ????

oneandonly

n=4

max=18750 A

waterdemon

I would like to mark the mistake of my mate "One and only one "

As he has taken Paschen Sereis and has made mistake

Inactual as it is given that Hydrogen atom is in ground state So we should take

n₁= 1 and thus it has to be Lyman sereis.

Since the Hydrogen atom is excited by a ray

With Wavelength of 970.6 A

So the nature of the wavelength is " U V Rays "

So the value of n₁ = 1 and n₂ = 2,3,4

That is it lies in the Lyman sereis

So the maximum value of the wavelength will be when H atom jumps to n₂ = 4

1 /

= Rh * Z² [(1/ n₁²) - ( 1 / n₂²)]

As per the formula

1 /

= 109678 [ 1/1 - 1/16 ]

1 /

= 109678 [ 15/16 ]

1 /

= 102823.13

Therefore We will get

= 1 / 102823.13

= 0.0000097

= 97000 A

OR

= 0.0000097 nm.

Solved.

plZ rate me for my efforts .

Cheers !!!!!!!!!!!!!!!!!!!!!

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