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Blazing goIITian

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4 Apr 2008 19:13:22 IST

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Photoelectric effect

None

If photoelectron emitted from the surface of a certain metal by light of frequency 2.2*10^15 hz are stopped by a reverse potential of 6.6V, the stopping potential when light of frequency 4.6*10^15 hz is used is..............

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Comments (9)

Tanmay

Blazing goIITian

Joined: 6 Sep 2007

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4 Apr 2008 19:18:03 IST

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ne1 plzzzzzz

sunip dutta

Scorching goIITian

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4 Apr 2008 19:19:13 IST

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is it 16.5 V

Glenn Jasper

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4 Apr 2008 19:20:36 IST

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is d ans 15V. if yes, ill giv u d solution

Tanmay

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4 Apr 2008 19:23:28 IST

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@sunip
ya the ans is 16.5

plz give detailed solution......

Glenn Jasper

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4 Apr 2008 19:28:10 IST

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v=h*freq/e-work fn/e

put d given values n find d work function.

using work funcion, u can calculate the stopping potential for the given frequency.

try it out dude, n tell me if u get d right ans!!!

Tanmay

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4 Apr 2008 19:29:55 IST

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wat is that e-work fn/e???

i didnt get it

Glenn Jasper

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4 Apr 2008 19:32:25 IST

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i meant-

v=1/e[h*freq - work function]

thats d formula for stoppin potential............

sunip dutta

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4 Apr 2008 19:33:10 IST

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_o )=eV_oV_o =stopping potential
so according to first information

=2.2*10^15
so putting it in the eqn we get h

_o =h(2.2*10^15)-(6.6ev)
now given in second information

=4.6*10^15
so h

-h

_o =eV_o
or eV₀ =26.4*10^-19 (putting all values
and value of h

₀ will be constant for the 2 eqns..)
or V₀ =16.5 V

rate if satisfied....

Glenn Jasper

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Joined: 7 Oct 2007

Posts: 129

4 Apr 2008 19:36:44 IST

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yeah, dats a better method. however, d other will also do...........

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