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Blazing goIITian

Joined:	21 Apr 2007
Post:	897

18 Mar 2008 13:43:37 IST

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Ratio of De-Broglie wavelengths

None

Q1.A particle of mass M at rest decays into two particles of masses m1 and m2 ,having non-zero velocities.The ratio of De-Broglie wavelengths of the particles , 1/2 is :

(A)m1/m2

(B)m2/m1

(C) 1:1

(D)sqrt(m2/m1)

Solve and get rates.

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Comments (3)

Akhil

Blazing goIITian

Joined: 17 Jan 2008

Posts: 1451

18 Mar 2008 13:44:49 IST

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C)?
It was initially at rest
so momentum=0
since momentum is conserved,
they move with equal and opposite momenta, ie P and -P
but
lamda=h/p
and p is same in magnitude
so 1:1

NITESH BASKARAN

Blazing goIITian

Joined: 29 Sep 2007

Posts: 487

18 Mar 2008 13:47:42 IST

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since decay occurs due to internal force the net momentum is conserved
let the velocities be v1 and v2
then
i have used ' l ' instead of lambda
m1v1=m2v2
v1/v2=m2/m1
(h / (m1 x l1)) / (h / (m2 x l2)) = m2/m1
therefore l1/l2 =1:1
hence (c)

manan shukla

Cool goIITian

Joined: 2 Jul 2007

Posts: 65

19 Mar 2008 16:33:54 IST

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due to momentum conservation ratio is 1:1

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