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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 13:43:37 IST
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Q1.A particle of mass M at rest decays into two particles of masses m1 and m2 ,having non-zero velocities.The ratio of De-Broglie wavelengths of the particles ,  1/2 is :
(A)m1/m2
(B)m2/m1
(C) 1:1
(D)sqrt(m2/m1)
Solve and get rates.
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"Nenenthedhavano naake teleedu"
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C)?
It was initially at rest
so momentum=0
since momentum is conserved,
they move with equal and opposite momenta, ie P and -P
but
lamda=h/p
and p is same in magnitude
so 1:1
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18 Mar 2008 13:47:42 IST
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since decay occurs due to internal force the net momentum is conserved
let the velocities be v1 and v2
then
i have used ' l ' instead of lambda
m1v1=m2v2
v1/v2=m2/m1
(h / (m1 x l1)) / (h / (m2 x l2)) = m2/m1
therefore l1/l2 =1:1
hence (c)
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19 Mar 2008 16:33:54 IST
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due to momentum conservation ratio is 1:1
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manan salman khan |
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