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12345 (2)

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obtain the amount of cobalt(27, 60) necessary to provide a radioactive source of 8mCi strength. half life of Cobalt27,60 is 5.3 years.

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12345 (2)

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please anyone answer my question

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icy_2291 (20)

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how to do this?

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please reply

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edison (4912)

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I think the data provided is insufficient as it is not only the mass or quantity of Co-60 that decides its activity but also the neuton flux and time in which it is kept for its neutron activation to take place consequent upon which it becomes radioactive.
 
Anyway u can use the concept that decay scheme of Co-60 is by emission of 2 gamma photons of energy 1.33Mev and 1.17Mev.

The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp.
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