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Modern Physics

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Joined:	7 Oct 2007
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4 Apr 2008 19:41:48 IST

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298

solve dis ques- frm H.C.Verma-

None

the electric field at a point associated with a light wave is

E=(100V/m)sin[(3 * 10^15)t] sin[(6 * 10^15)t].

If this light falls on a metal surface having a work function of 2eV, what will be the maximum kinetic energy of the photoelectrons?

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Comments (5)

Tanmay

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4 Apr 2008 19:47:18 IST

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he he good question!!

Glenn Jasper

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Joined: 7 Oct 2007

Posts: 129

4 Apr 2008 19:47:59 IST

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sum1 reply.............

Glenn Jasper

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Joined: 7 Oct 2007

Posts: 129

4 Apr 2008 20:13:18 IST

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cumon guye, dont let me down................

arpan1

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4 Apr 2008 20:18:26 IST

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this is easy

from the given eqn. u can get the frequency (f) of incident radiation

then

k.e. = hf - w

one more point

since the above eqn. is in form of 2 sin functions
rewrite it by using 2sin a.sinb = sin (a +b).sin(a - b)

rate me

mohit patni

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4 Apr 2008 20:22:03 IST

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wat arpan told is right...

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