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Modern Physics

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5 Apr 2008 23:44:41 IST

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482

solve fast...............

None

the max speed of emitted electron in a photoelectric experiment is 2* 10^6 m/s. If a uniform magnetic field of 5* 10^-5 T is applied perpendicular to the plane of motion, the radius of the path followed by the electrons will b.............plz give detailed soln.............

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Glenn Jasper

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5 Apr 2008 23:47:09 IST

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sum1 solve quickly.........no dude over here???!!!

SRM

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5 Apr 2008 23:50:10 IST

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circular

v = 2* 10⁶m/s

B= 5*10^-5T

F= evB= (mv²)/r

(since centripetalforce=magnetic lorentz force..)

subst. values and hence obtain ans...

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SRM

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5 Apr 2008 23:51:10 IST

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does it suffice for a dudette to solve it..or even try??

Glenn Jasper

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5 Apr 2008 23:52:45 IST

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detailed ans plz........

nice joke...........

SRM

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5 Apr 2008 23:55:29 IST

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well is it rite or wrong??? please acknowledge... sorry if i offended you...

Glenn Jasper

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5 Apr 2008 23:57:43 IST

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u hve 2 giv the radius in terms of units shesha.........ans is 0.23m

no offence.........

SRM

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6 Apr 2008 00:04:28 IST

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please see edited

chemicaltester

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6 Apr 2008 00:15:45 IST

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see the centripetal force require for circular motion is provided by magnetic force
hence cpp =BeV
so Mv^2/r =bev

so r =mv/be
now e is 1.6 *10^-19
m =9.1 *10^-31

solving u will get the answer =0.225m

Tanmay

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6 Apr 2008 06:24:13 IST

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it's so easy

equate mv^2/r=evB

r=mv/eB
put the appropriate values
m=9.1*10^-31
etc

u get r=0.23m

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