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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Urgent..plz solve
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[Post New]10 Jun 2008 16:30:19 IST
    Subject: Urgent..plz solve
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anpm_dev (111)

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Monochromatic light of wavelength 3000  is incident on a surface area 4 cm2. If intensity of light is 150 mW/m2, then rate at which photons strike the target is




  1. 3 x 1010 /sec





  2. 9 x 1013 /sec





  3. 7 x 1015 /sec




  4. 6 x 1019 /sec




detailed explaination plz.......
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[Post New]10 Jun 2008 16:44:51 IST
    Subject: Urgent..plz solve
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pink_ele (1233)

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energy of each photon=hc/lambda=6.626x10^-19 J
now,
intensity=power delivered per squre m
150mW per squre m=>6 x 10^-5W per 4cm sq
i.e.....no of photons= 6x 10^-5/(6.626 x 10^-19)
=9.05x 10^-13
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[Post New]17 Jun 2008 16:40:04 IST
    Subject: Re:Urgent..plz solve
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sathya_crazyteen (122)

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ENERGY OF EACH PROTON = hc/lambda=      6.626 x 10-19 J


intensity = 150 x 10-3 w


1 sq metre         -----------------------    150 x 10 -3 w


4 x 10-4 metre------------------------?     ---->6 x 10 -5 w


no of protons = 6 x 10-5/6.626 x 10 -19 == 9.05 x 10-13
sathya prabha girish
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