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9 Jan 2010 17:22:06 IST
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how can you find number of images formed by inclined mirrors by plotting ray diagrams?
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how can you find number of images formed by inclined mirrors by plotting ray diagrams?


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Blazing goIITian

Joined: 7 May 2007
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9 Jan 2010 19:39:11 IST
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the number of images will be equal to the number of mirrors.

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Cool goIITian

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10 Jan 2010 10:58:50 IST
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2  mirrors are inclined at an angle 60degree  .An object lies on a line inclined at an angle 30degree with any one of the mirrors.How can you find number of images formed by the two mirrors by plotting ray  diagram?

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Joined: 2 Dec 2007
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10 Jan 2010 11:04:12 IST
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360/theta - 1 is the formula for this........360/60 -1 = 5
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10 Jan 2010 12:02:30 IST
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Out of these 5 images , how  can we find number of images formed by each mirror?(plz  use ray diagrams)

aswin the great's Avatar

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14 Jan 2010 17:03:56 IST
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nyone plzzz   help

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25 Jan 2010 22:52:30 IST
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plzzzz  i want help  ....................

is there anyone i've  been waiting  for so looooooooooong

Sagar Saxena's Avatar

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27 Feb 2011 08:56:42 IST
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hi

Image Formation When an Object is Placed between Two Inclined Mirrors

It has been found that if the mirrors are inclined at an angle

q

then the number of images is given by the relation 

If

is not a whole number, then the number of images will be rounded off to the nearest integer. This can be verified by actual drawing.

If the mirrors are inclined at 120o the number of images formed by the mirrors is given by the relation 

Case - I

Let MM and MM' be two plane mirrors inclined at an angle 120

o

and O be the object placed in between these mirrors. In this case there will be only two images viz., O

1

and O

2

.

image formation of plane mirrors which are inclined at an angle 120 degrees

Case II

Now let us consider the mirrors MM and MM' to be mutually perpendicular. In this case the number of images formed by the mirror is

image formation of plane mirrors which are inclined at an angle 90 degrees

The Angle of Inclination Between the Mirrors is 90

0

.

  • Place the mirrors MM' perpendicular to MM.
  • An object O is kept in between these mirrors.
  • OA and OB are the two rays, which are incident on the mirror MM.
  • OA being normal to the surface retraces its path.
  • OB makes an angle i with the normal N and gets reflected along BC according to the laws of reflection
  • Extend the rays OA and BC backwards.
  • They meet at O1, which is the virtual image of O.
  • OD and OE represent the rays which are incident on the mirror MM'.
  • OD is perpendicular to the mirror MM' and hence gets reflected along the same path.
  • OE is the incidentray and N2 is the normal at the point of incidence and OE gets reflected along the path EF.
  • Extend OD and EF backwards. They meet at O2, which is the virtual image of O.
  • The reflected ray BC gets internally reflected by the mirror MM' along CG.
  • The ray DG appears to comes from O3, which is the image of O1,
  • Similarly EF the reflected ray gets internally reflected by the mirror MM along FH.
  • The ray FH appears to come from O4, which is the image of O2.
  • The position of O1 and O2 coincide.
  • Thus when the angle of inclination between the mirrors is 900 we get three images.

Case III

Let us now calculate the number of images formed if the two mirrors are placed parallel to each other i.e., the angle of inclination between them is 0

0

.

image formation of plane mirrors which are inclined at an angle 0 degree
  • Place the mirrors MM and MM' parallel to each other.
  • An object O is kept between these mirrors.
  • OA and OO' represent the rays which are incident on the mirror MM.
  • OO' being normal retraces its path.
  • OA makes an angle i with the normal N1 and gets reflected along AB according to the laws of reflection.
  • Extend the rays AB and OM backwards.
  • They meet at I1, which is the virtual image of the object O.
  • The reflected ray AB gets reflected by the mirror MM' and forms an image I2.
  • Similarly I3, I4 etc. are formed.
  • The light from I1, I2, I3, I4 etc. gets reflected and forms their images.

In this manner, many images are formed but the intensity of the remote images goes on decreasing due to absorption of light energy at every successive reflection and thus we see only finite number of images even though infinite images will be formed !!!!!



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Joined: 22 Dec 2011
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22 Dec 2011 09:42:11 IST
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how can you find number of images formed by inclined mirrors by plotting ray diagrams?



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