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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Oct 2007 09:18:12 IST
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How to find acidity (comparitive) for molecules such as these: CH 3C  CH CH3CH=CH2 CH3CH2CH3 like how to arrance them in ascending order of acidity? plz help.....
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SiNcY... |
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20 Oct 2007 11:10:02 IST
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sp is more electro negetive than sp2 which more elctro- ve than sp3
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20 Oct 2007 11:12:45 IST
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I think it is b a c the decresing order.......as secod one it is allylic alpha carbon not sure .............
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20 Oct 2007 14:58:07 IST
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the increasing acidity order is CH3CH2CH3 CH3CH=CH2 CH 3C CH this is due to increasing s character
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20 Oct 2007 19:02:08 IST
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as the s charecter of orbital increase electron are drown closer to nucleus so electrnegativity increase so sp>sp2>sp3 is E N order so alkyne is maximum acidic than alkene than alkane.
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Arun / Rashi - Authors Macromind MCQ of Chemistry from G.R Batla |
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20 Oct 2007 19:20:26 IST
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i think the correct order would be..
CH3CCH>CH3CH=CH2>CH3CH2CH3
bcos...s character of the orbital increases , electrons r attracted or drawn nearer to the nucleus due to which the electronegativeity is more in alkyne thn in alkene and alkane...
hence the acidity is more in alkynes rather thn in alkenes and alkanes..
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"your future depends on what u do in present"
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