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nik_gup (196)

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Write formula for product of the reaction of 2Methyl Hexene with each of following:-
a)HBr in presence of light
b)catalytic reduction with H2
c)dil. alkaline KMnO4
d)Hypochlorous acid
e)cold conc.H2SO4
f)Bromine
g)Iodine

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srini (395)

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Hey,
a)2bromo 2methyl hexane(no anti markonikov)
b)2methyl hexane
c)2 methyl hexane-1,2 -diol.
d) not
e) dsure
f)1,2 dibromo 2methyl hexane
g)

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arun-rashi (1131)

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a.this reaction is HBr in presence of peroxide so formation of free radical and free radical addition reaction takes place.ans is BrCH2-CH(CH3)-CH2CH2CH2CH3  b.this reaction is catalytic hydrogenation so product is 2-methyl hexane

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c.alkenes reacts with cold KMnO4 so this oxidation reaction .in this reaction cis hydroxylation takes place.first cis addition of KMnO4 than hydrolysis with water to give 2-methyl hexane cis 1,2-diol. d.next reaction is halohydroxylation by hypochlorous acid.first formation of cyclic halonium ion than back attack of hydroxy anion takes place which give trans 1-chloro 2-methyl 2-hexanol.

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alkenes reacts with con.H2SO4 is an example of addition of H2SO4.this is break down into H+ and -OSO3H  so product is CH3-C(OSO3H)CH3-CH2CH2CH2CH3

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with Br2 first formation of cyclic halonium ion takes place than trans dihalo product formed across double bond.similar reaction with iodine.

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