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3 Aug 2009 21:07:16 IST

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arrange yhe molecules in decreasing order of stability (CH3)3C+,C6H5CH2+,C6H5+,CH2=CH+,C2H5+

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arrange yhe molecules in decreasing order of stability (CH3)3C+,C6H5CH2+,C6H5+,CH2=CH+,C2H5+

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Rohit

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3 Aug 2009 21:14:18 IST

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I > II > V > IV > III. Do tell me the answer by nudging please.

zzzzz

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3 Aug 2009 21:19:56 IST

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C6H5CH2+ > (CH3)3C > CH2=CH+ > C2H5+ >C6H5+IS IT CORRECT???

Rohit

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3 Aug 2009 21:24:27 IST

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Gaurav can I discuss this question with you? shouldn't tertiarly carbocation be the most stable among this... I 'm probably wrong in assigning vinyl carbocation(CH2=CH+) and ethyl carbocation (CH3-CH2+).

dc16

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3 Aug 2009 21:46:43 IST

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C2H5+ > C6H5+

i think C6H5+ should be more stable than C2H5+

ANd mr. rohit .. benzyl cation is more stable than tertiary butyl carbocation .

Akshay

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3 Aug 2009 21:49:18 IST

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the correct ans must be C6H5CH2+ > (CH3)3C+ > C2H5+ >CH2=CH+ > C6H5+......I AM SURE THIS ANS IS CORRECT

dc16

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3 Aug 2009 21:56:16 IST

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yea rite

Akshay

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3 Aug 2009 22:04:33 IST

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did u read the reason??

Akshay

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3 Aug 2009 22:27:49 IST

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reason between CH2=CH+ and C2H5+ is that CH2=CH+ is highly unstable....

zzzzz

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3 Aug 2009 23:02:05 IST

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@Rohit

srry dude i was offline then...........

Nahor

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4 Aug 2009 19:10:33 IST

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already solved.

Madhusudan Chavan

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6 Aug 2009 15:58:39 IST

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The relative stability of carbocations can be measured through heterolytic bond dissociation energies. The lower the value of of heterolytic bond dissociation energy, greater is the stability of the carbocation. Thus the order of stability along with bond dissociation energies in kJ / mole is as follows :

t-butyl ( 657) > benzyl (695) > isopropyl (711) > allyl (724) > n-propyl (744) > ethyl (799) > vinyl (866) > methyl (952) > phenyl (916).

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