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Organic Chemistry

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17 Feb 2009 12:09:41 IST
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CHECK UR ORGANIC SKILLS........
None

CHECK UR ORGANIC SKILLS........

 

 

(CH3)3 Br   +   HC (triple bond) C-- Na +     ---------------->

 


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KRRISH's Avatar

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17 Feb 2009 12:13:26 IST
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were to check.

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17 Feb 2009 12:17:34 IST
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?
pranav agrawal's Avatar

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17 Feb 2009 12:24:40 IST
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sorry i dnt know y the image is not uplodaing...??i m trying wait...
pranav agrawal's Avatar

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17 Feb 2009 12:30:53 IST
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check this simple one...
KRRISH's Avatar

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17 Feb 2009 12:58:28 IST
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CH(triple bond)C-C(CH3). is it right
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17 Feb 2009 13:02:31 IST
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NO!!!!!!!!!!!! if it had been so easy, why would i asked it??? he he lol////try again...
pranav agrawal's Avatar

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17 Feb 2009 13:06:13 IST
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once you have done it, try this also .......................................................propyne is allowed to react with B2 D6 and the product is treated with acetic acid.................................then what is final product formed??????????????just type the formula...(this is easy)
abhishek's Avatar

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17 Feb 2009 13:26:03 IST
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Is the ans (CH3)2-C=CH2

pranav agrawal's Avatar

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17 Feb 2009 13:28:20 IST
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YES YOU GOT THAT RIGHT ABHI.......................BUT HOW???TELL YAAR..............TRY THIS ONE ALSO........propyne is allowed to react with B2 D6 and the product is treated with acetic acid.................................then what is final product formed??????????????just type the formula...(this is easy)
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17 Feb 2009 15:57:26 IST
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Yes the answer to your previous question is (CH3)2-CH=CH2.

The reason for this answer is:- Since the halide given is tertiary, so instead of substitution, elimination reaction by the base takes place.

 

The answer to your other question is:- CH3-CD=CHD

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17 Feb 2009 16:01:13 IST
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is it (CH3)3CBr or (CH3)3Br . well if it is the first one then........CH(triple bond)C- Na+ breaks into CH(Triple bond)C- and Na+. the former attacks one of the primary carbon atom and extracts H+ from it. thus a primary carbanion. Now it donates its -ve charge to the C-C bond forming (CH3)2-C=CH2 and Br leaves as NaBr.
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17 Feb 2009 16:09:07 IST
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Answer to your 2nd ques-->

CH3-CH2D-CHO

 

CORRECT?

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17 Feb 2009 16:27:49 IST
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Swaprules, the answer that you have given would be correct if instead of Acetic acid, we use . If that would have been the case, then also CH3-CD2-CHO would have formed.

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17 Feb 2009 16:28:08 IST
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the 2nd product is CH3-CH=CHD
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17 Feb 2009 16:34:58 IST
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JPS, since we are carrying out the reaction with B2D6 , so don't you think CH3-CD=CHD  would be formed, instead of the compound you have given. This is beacuse there is no source of hydrogen atoms. We are given with B2D6, and not B2H6.

 

If there are any errors in my answer, then please correct it.

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17 Feb 2009 16:42:55 IST
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you are Mr. ashish kumar..........the correct answer to 2nd question is wht u have typed...
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17 Feb 2009 16:43:26 IST
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@ashish after reacting with B2D6 we are reacting it with acetic acid whic becomes the source of H+ ions. D+ ions r used up in the formation of the intermediate. moreover i think it should be peracetic acid instead of acetic acid(taking into consideration the mechanism). lets wait for the answer.
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17 Feb 2009 16:46:51 IST
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try this one..........

CYCLOHEXENE ON REACTION WITH Br2 IN CCl4 YIELDS.......

1.) CIS 1,2 DIBROMOCYCLOHEXANE

2.) TRANS 1,2 DIBROMOCYCLOHEXANE

3.) (+ -) TRANS 1,2 DIBROMOCYCLOHEXANE

4.) MESO 1,2 DIBROMOCYCLOHEXANE

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17 Feb 2009 23:46:24 IST
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ans is (+ -) TRANS 1,2 DIBROMOCYCLOHEXANE



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