hey aman if u will use NO2+ THEN THE PARA will also be formed.............
so the major concern is to make 100% ortho...........
for this ..............para should be blocked..............ok.........
now.............
C6H5CH3 + ( CH3)3Br ---> (CH3)3--C6H5- CH3
[ NOTE : HERE ORTHO WILL NOT BE FORMED BECAUSE........
due to stearic hindrance..........only para will be formed]
now use NO2+ REAGENT............NO2 WILL HAVE NO OPTION BUT JUST ...IT WILL ATTACH TO ORTHO.............
NOW..............REDUCE IT BY Sn/HCl.............to NH2............
USE NaNO2 / HCl AND then CuBr................
the desired product will be obtained.................
thanku...........