IIT JEE , AIEEE Forum - Chemistry , Organic Chemistry

sreemoyee07

from CH2=CH2 to CH3-CH=CH2

destinationIIT09

CH2=CH2 + KCN ------> CH3CH2CN

CH3CH2CN + HCl --------->CH3CH2CH2Cl

DEHYDROHALOGENATION:-

CH3CH2CH2Cl + alchoholic KOH----->CH3-CH=CH2

destinationIIT09

RATE IF FOUND USEFUL

adityaraj

another way to do it.

1> ozonolysis gives formaldehyde.

HCHO + ethyl magnesium bromide gives propyl alcohol.

propanol + dehydration with sulphuric acid give propene

layman

1)CH2=CH2 + Br2/CCl4--> CH2Br-CH2Br

2)CH2Br-CH2Br + alc.NaNH2 --> ETHYNE

3)ETHYNE + NaNH2 --> sodium acetylide

4)sodium acetylide + CH3-I --> propyne

5)propyne + lindlar's catalyst --> propene

layman

And "Destination" your second step is wrong. It will give a carboxylic acid.

computer001

layman where does oh come from to form a carboxylic acid???

sandeepramesh

My method :D

1. Oxo process

2. LAH

3. conc H2SO4

layman

computer001 what phase is HCl in?

computer001

its not necessary it has to be aqueous...jus cuz v deal gnly only wid aq hcl it does not mean always it has to be so

computer001

The compound hydrogen chloride has the formula H Cl. At room temperature, it is a colorless gas, which forms white fumes of hydrochloric acid upon contact with atmospheric humidity. The formula HCl is often used to refer, somewhat misleadingly, to hydrochloric acid, an aqueous solution derived from hydrogen chloride.

pardesi

1.B2H6 followed by acetic acid(gives u propane)

2.chlorination(gives u 1or 2-chloropropanes)

3.treat the mixture with Alc.KOH to get 1-propene

layman

cyanide on reaction with HCl --> what then computer001?

layman

And pardesi your first step will give ethane and not propane

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