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joyfrancis (1504)

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Q). An organic compound (A) of m.f C7H12O containing no double bonds on treatment with an eq. of  HCl gives 2-chloro-2-methyl-hexan-5-ol. Identify (A)

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astronautameya (267)

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r u sure u've named the product correctly?
where is the 1-position on the hexane ring?

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joyfrancis (1504)

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2-chloro-2-methyl-hexan-5-ol
 


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spideyunlimited (3083)

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C 6 H 10 - CH - OH ...
cant guess the IUPAC name though...

in the figure uve drawn.. it will be without all those attacments and at position 2, u will have CH - OH .
 
 
 
is it called hexyl alcohol?


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joyfrancis (1504)

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give the structure , draw it on paint , convert to jpeg format and attatch.

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spideyunlimited (3083)

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this is the compound



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joyfrancis (1504)

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incorrect.

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DEXTERprashant (29)

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joyfrancis (1504)

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nope, the compound contains no double bonds , read the qn

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aankurverma (1320)

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CH3 - (CH 2) 5 - CH 2OH  2-CHLORO 2 -METHYL HEXANE - 5 -OL
 
                          O HAS + SIGN ON IT ACTUALLY O HAS TAKEN H+  FRM HCl                                        
CH 3 - (CH 2)5 -CH 2-OH2       CH 3 -CH 2-(CH 2)4 - CH 2    
 
RING EXPANSION 6 MEMBER RING IS FAVOURED IN PLACE OF 7 DUE TO STABILITY HENCE SIX MEMBERED RING WILL B FORMED AND THEN CL- WILL ATTACH ON CARBON
 
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spideyunlimited (3083)

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oh sorry i didnt read properly.. this is the compound. H on 2nd carbon gets replaced by Cl.



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spideyunlimited (3083)

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2 methyl hexan 5 ol


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joyfrancis (1504)

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nope!

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khinart (198)

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tHE ANSWER IS 2-CHLORO- 2-METHYLHEXANE-5-OL

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