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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 01:04:54 IST
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pls solve
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 01:08:17 IST
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i want to ask how stability of 5 and 3 has been compared?????
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 01:16:06 IST
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5 has more resonance structures than 3. so its more stable.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 01:34:57 IST
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HOW CAN U SHOW RESONANCE IN 5??
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 11:05:07 IST
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Hmmm...I dont get how V is least stable when it has max reso structures and the lone pair is getting delocalised maximum.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 11:55:50 IST
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no rooney there is no lone pair delocalization in either of them. look carefully the carbon is a free radical
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 12:33:31 IST
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See in the other structures carbene may form in trying out resonance hence they are most unstable.Further onehaving three pi bonds in ring forces carbene formation more than the single bond ring.Hence the result................ I have tried to answer in common language for your comfort................
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Being a genius is 1% luck and 99% perspiration........ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 12:37:05 IST
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in 5 aromaticity of benzene ring has damaged bcoz it now does not follw (4n+2)pie syatem so it is the least stable others can be judged in different ways hope u can make it now
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 12:37:56 IST
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Been long since I did organic. Anyways, isnt this what happens ?

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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 13:18:31 IST
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@mukuluss, aromaticity gives extra stability to compounds than other comparable non aromatic compounds,and absence of it doesn'dt redues the stablity(than the nortmal value),isnt it????????
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Nov 2007 13:25:33 IST
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@rooney two consecutive double bond in any ring system is not possible, due to very high angle strain , so resonance shown by u are not possible.....
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Nov 2007 14:20:27 IST
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Stability of free radical depends on i) Hyperconjugation and ii) resonance effect. In case of IV & II resonance effect can expalin the stability. In case of phenyl free radical no other structure would be possible hence is least stable.For structure III, one structure may be possible by using hydrogen atom on adjacent carbon( benzyne type triple bond). Hence III should be more stable than V. However, the same anology does not work for vinyl free radical, it is less stable than phenyl free radical.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Nov 2007 17:20:07 IST
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if triple bond resonance is possibnle in III tehn why it is not possible in V ???????
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Nov 2007 00:59:30 IST
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v is aromatic so it has to b most stable.......ans gvn is wrong
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 12:09:50 IST
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