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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 May 2007 10:38:32 IST
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Hi, Can someone explain the answer to this question? How many geometrical isomers are possible for the compound: My book says the answer is 3.. But I can only make out 2.. Please tell me how.
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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I hope ths ll help.............. followin r d 3 geometrical isomers possible
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 May 2007 10:54:26 IST
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There are two double bonds in the compound. So you get for combinations: 1.) Cis - Trans 2.)Cis - Cis 3.)Trans - Cis 4.)Trans - Trans Now write down all four. You will see that the cis - trans isomer and the trans - cis isomer are same.this is because the molecule is symmetric from both sides. So you get 4-1=3. Please rate my nswer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 May 2007 15:16:56 IST
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the three isomers will be.....
2-Z,4-Z
2-E,4-E
2-Z,4-E
plz rate the ans
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never curse ur conditions....ask urself wt all sincerity...whether u r doing ur best or not?...u wl get the ans n get started.......GOODLUCK Dr. Meenal |
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