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rohanrony (17)

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CH3--(CH3)2CONa  +   CH2=CH2--Br   =
    
rohanrony (17)

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pls find an anser for me
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arpan1 (665)

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do u need the ans right now

see i can provide u a better solution tommorow

is that o.k. with u

all the best ...
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ananth_patri (585)

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may be NaBr separates out and the remaining forms CH3--(CH3)2-CO-CH=CH2 is it rite??

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rohanrony (17)

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is there any effect of double bond?
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ananth_patri (585)

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ya well in my product there is resonance betw the = and CO no?? is it rite??

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rohanrony (17)

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IN MY TEXT the mechnisn of this reaction is not given so i cant under stan d how it takes place

if , ananth can u find the mech of this
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rakesh61 (1884)

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CH3--(CH3)2COCH=CH2

its simply an electrophillic substitution reaction

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magaishwarya (136)

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CH3(CH2)2COCH2=CH2
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harsha_27 (1343)

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First notice few things here

1.Nucleophile is bulky, so it is a very good base than a nucleophile(just like potassium ter-butoxide).
2.The carbon attached to Br is vinylic,I mean vinylic bonds are very strong and do not break that easily.

So I think elimination predominates substitution here.

The major product will be an E2 based Dehydrohalogenation.

So H-CC-H ,acetylene, will be the major product.





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