Home » Ask & Discuss » Chemistry. » Organic Chemistry « Back to Discussion



Organic Chemistry

Smruti Modi's Avatar
New kid on the Block

Joined: 13 Oct 2007
Post: 3
31 Oct 2007 17:41:26 IST
0 People liked this
2
688 View Post
Markownikoff's Rule
None

if the reaction of any unsymmetrical carbon compound is carried in presence of peroxide,                    
e.g.-CH3-CH=CH2+HBr
then the product formed contains only 1-bromopropane
But in the absence of peroxide,why 1-bromopropane is also formed if we are considering Markownikoff's rule.Because it is given in a book which i refer that in absence of peroxide,the product which we get contains approximately 90% of 2-bromopropane and 10% of 1-bromopropane?
                                  


Share this article on:

Comments (2)

Nadeem's Avatar

Blazing goIITian

Joined: 25 Aug 2007
Posts: 521
31 Oct 2007 18:19:29 IST
0 people liked this

Markovnikov 's rule states that in the absence of peroxide, 2-bromopropane will be  the major product. It does not mention that it will be the only  product . What is written in the buk is right.
arun-rashi's Avatar

Forum Expert
Joined: 19 Oct 2006
Posts: 1057
1 Nov 2007 07:49:09 IST
0 people liked this

in presence of peroxide there is free radical addition reaction ouccrs so major is 1-bromopropane by intermediate free radical stability but in absence of peroxide ionic electrophilic addition so major is 2-bromopropane and minor 1-bromo product.



Quick Reply


Reply

Some HTML allowed.
Keep your comments above the belt or risk having them deleted.
Signup for a avatar to have your pictures show up by your comment
If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Find Posts by Topics

Physics.

Topics

Mathematics.

Chemistry.

Biology

Parents

Board

Fun Zone

Sponsored Ads