Home » Ask & Discuss » Chemistry. » Organic Chemistry « Back to Discussion
Organic Chemistry
Markownikoff's Rule
None
if the reaction of any unsymmetrical carbon compound is carried in presence of peroxide,
e.g.-CH3-CH=CH2+HBr
then the product formed contains only 1-bromopropane
But in the absence of peroxide,why 1-bromopropane is also formed if we are considering Markownikoff's rule.Because it is given in a book which i refer that in absence of peroxide,the product which we get contains approximately 90% of 2-bromopropane and 10% of 1-bromopropane?
Comments (2)
Nadeem
Blazing goIITian

Joined: 25 Aug 2007
Posts: 521
31 Oct 2007 18:19:29 IST
Like
0 people liked this
Markovnikov 's rule states that in the absence of peroxide, 2-bromopropane will be the major product. It does not mention that it will be the only product . What is written in the buk is right.
Reply
1 Nov 2007 07:49:09 IST
Like
0 people liked this
in presence of peroxide there is free radical addition reaction ouccrs so major is 1-bromopropane by intermediate free radical stability but in absence of peroxide ionic electrophilic addition so major is 2-bromopropane and minor 1-bromo product.











