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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 18:33:53 IST
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CH3COCH3 LAH ) () H+/Br2+CCl4___)()NaNH2liq NH3 _)() Na liq NH3___)X X IS : A) Trans CH3CHCHCH3 B) Cis CH3CHCHCH3 C) CH3CCH D) CH3CCNa
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 18:47:12 IST
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is the answer A
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 18:48:13 IST
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please explain ur answer..!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 18:54:28 IST
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in the first step CH3CHOHCH3 WILL BE FORMED I'VE SOME CONFUSION IN THE NEXT STEP IF WE GET CH3CCCH3 IN THE THIRD STEP, Na/NH3 WILL REDUCE IT PARTIALLY AND IN THE ANTI SENSE FORMING TRANS CH3CHCHCH3
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 19:12:34 IST
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first step is correct by rhd92781. but after than that, there will be substituition of Br which will be reduced (dehydrohalogenation) to alkene n then on......
let me see then i will post detailed soln....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 19:20:06 IST
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I think d will be the answer..........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 19:39:33 IST
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see.......in the first step, CH2CHCH3 ,propene will be formed........ second step results in trans addition of bromine........... in third step propyne will be formed........... and at last Na will replace terminal hydrogen............ and final product will be D.......... that's my solution........... pls tell if i m wrong any where............ other wise rate................... sinjan , if i am correct...........then post it on 123........
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my future signature:
LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.
Happiness can be found, even in the darkest of times, if one only remembers to turn on the light.
Albus Dumbledore
Harry Potter and the Prisoner of Azkaban movie
There are only two ways to live your life. One is as though nothing is a miracle. The other is as though everything is a miracle.
-- Albert Einstein
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 19:45:02 IST
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i agree with lokeshsardana, but i dont think that LAH will convert acetone to propene,but instead i think 2-propanol will be formed
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Nov 2007 22:10:37 IST
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first propan-2-ol will be formed then it will lose one water molecule to give propene............
hey guys atleast rate my efforts yaar!!!!!!
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my future signature:
LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.
Happiness can be found, even in the darkest of times, if one only remembers to turn on the light.
Albus Dumbledore
Harry Potter and the Prisoner of Azkaban movie
There are only two ways to live your life. One is as though nothing is a miracle. The other is as though everything is a miracle.
-- Albert Einstein
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Dec 2007 19:48:51 IST
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propene should be the final product
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Dec 2007 20:12:47 IST
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@ great dreams
I know yaar! as Na + NH3 is reducing agent .......and will reduce.....
propyne to propene................but it is not given in options.........
so, I formed the product of rxn with only Na...........
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my future signature:
LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.
Happiness can be found, even in the darkest of times, if one only remembers to turn on the light.
Albus Dumbledore
Harry Potter and the Prisoner of Azkaban movie
There are only two ways to live your life. One is as though nothing is a miracle. The other is as though everything is a miracle.
-- Albert Einstein
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Dec 2007 12:46:48 IST
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I agree with lokeshsardana.In the first lithium aluminum hydride will reduce keytone top a secondary alcohol which is CH3CHOHCH3.Now the acid will convert it to prop-1-ene and then there will be a trans addition of bromine forming CH3CHBRCH2BR.Then Sodium amide will convert it into Prop-1-yne and Na/NH3 will replace the terminal hydrogen.so answer is d.
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