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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:51:04 IST
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suggest a suitable method for the following conversion see the image below
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"Imagination is more important than knowledge."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:53:24 IST
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edit sorry... i reversed the reaction :O
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:53:52 IST
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first react it with 2 moles of any alcohol ...then reduce the comp with sodium borohydride..and then do acidic hydrolysis.....the func of alcohol is that it will protect the aldehyde from being reduced
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:57:13 IST
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@akhil PCC oxidises here we want reduction
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:57:49 IST
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@sunip canu give me a mechanism of the reaction pls..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 22:05:47 IST
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i hope LiAlH4 will do the needful
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all the best ... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 22:09:36 IST
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yup lialh4 will do the job............. will reuce the ketone first to corresponding alcohol........
excess of it will reduce aldehyde ....as well
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" the only thing thats always constant in this world , is change itself.....
so it is better to adapt to the situation or life makes you adapt to it (painfully)..."
- Kundan a.k.a Juan dankh......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 22:11:59 IST
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no LiAlh4 reduces both the groups CHO and =O so u ll have to protect the CHO group..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 22:17:01 IST
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ya , i think ananth is right
lemme think then
will post soon
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all the best ... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 22:39:19 IST
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first do schmidt reaction that will convert CHO to CN....it will not affect the ketone..... then use meerwein-pondorf-verley reduction..... that will reduce C=O to CH--OH........ it will not affect the CN group........ then hydrolyse and convert CN to COOH..... then convert to COCl.... then do rosenmund reduction to get back the aldehyde group........ reagents for the reactions are..... schmidt reaction-->hydrazoic acid(HN3)+conc H2SO4 meerwein pondorf verley reduction---->aluminium iso propoxide rosenmund reduction----->H2/palldium/BaSO4/quinoline please tell me if there is any error in my steps......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Apr 2008 14:41:49 IST
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first oxidise the CHO grp to COOH with PCC.C=O will not b affected. now reduce C=O grp using H2/Pd to CHOH.COOH will be unreactive to H2/Pd.convert COOH to COCl and do rosunmund's reduction to get back CHO grp. plz tell me if there is anything wrong in this method !!!!!!!!!!!!!!!!!!!!!!!!
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Varsha
be cool,
tomorrow is what we make it today,
so if u can dream it , u can make it .
life is an ice cream ,eat it before it melts away!!!!!!!!!
    

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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Apr 2008 15:24:32 IST
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Protect the aldehyde using glycol(converted into acetal). Then reduce using LiAlH4 and finally hydrolyse to get the product.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Apr 2008 16:38:10 IST
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protect the aldehyde by glycerol( diol), reduce the keto by nabh4, hydrolyse it to the protected gp.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Apr 2008 17:15:01 IST
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varshavallig's method is correct.......
layman and karthik2789 ...... when you try to protect the aldehyde group using glycerol....... even ketone is protected.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Apr 2008 18:33:44 IST
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