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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jun 2008 00:46:02 IST
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ques 1
cyclohexene in presence of kmno4 gives syn addn
in presence of rco3h/h+ gives a trans addn
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" I've shed many tears. But after, I realize, why am I crying? No matter how bad it got, it could be worse. No matter how much you think it's not going to be ok, eventually it will be. You just have to let it be."
EXPECT MORE FROM URSELF THAN FRM OTHERS AS EXPECTATION FRM OTHERS HURTS U WHILE FROM UR SELF INSPIRES U A lot |
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16 Jun 2008 01:04:00 IST
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arre pls some one reply karo pls !
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" I've shed many tears. But after, I realize, why am I crying? No matter how bad it got, it could be worse. No matter how much you think it's not going to be ok, eventually it will be. You just have to let it be."
EXPECT MORE FROM URSELF THAN FRM OTHERS AS EXPECTATION FRM OTHERS HURTS U WHILE FROM UR SELF INSPIRES U A lot |
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16 Jun 2008 13:51:49 IST
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well it is due to its mechanism...in presence of rco3h it takes place via free radical mechanism so u get trans product.....
i hope im rite......
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16 Jun 2008 14:08:48 IST
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hey pls give mech if possible
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" I've shed many tears. But after, I realize, why am I crying? No matter how bad it got, it could be worse. No matter how much you think it's not going to be ok, eventually it will be. You just have to let it be."
EXPECT MORE FROM URSELF THAN FRM OTHERS AS EXPECTATION FRM OTHERS HURTS U WHILE FROM UR SELF INSPIRES U A lot |
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16 Jun 2008 23:50:00 IST
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The reaction with MnO4- ion gives syn addition because two oxygens on the ion add to the double bond at the same time to give an intermediate that has a ring of two carbons, two oxygens, and the Mn atom - so the two oxygens must add from the same side. In aqueous base the bonds to the Mn break to give a diol.
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17 Jun 2008 15:00:46 IST
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i think the reaction with KMnO4 will proceed further to form a hexane 1,6 di oic acid. reaction of cyclo hexane with KMnO4 is there in school text solved example i think it is carboxylic acid chapter if u want to know the page no. then tell me
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