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Organic Chemistry

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20 Oct 2007 09:13:03 IST

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Question in Hybridisation

None

Hybridisation of carbon atoms in CH₃-C

C-CH_{3 is}

a) sp³ and sp²

b) sp³ and sp

c) sp² and sp

d) sp only

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santhosh in NUS

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Joined: 13 Aug 2007

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20 Oct 2007 09:50:06 IST

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OPTION IS B.

SP3 - SP -SP - SP3

CH₃-C

C-CH₃

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viswesh Nrayanan

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20 Oct 2007 11:07:55 IST

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FROM LEFT
1st- sp3 terathydral 109 d 28'
2nd-sp linear 180 d
3rd-sp linear 180 d
4th -sp3 terathydral 109 d 28'

viswesh Nrayanan

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20 Oct 2007 11:08:42 IST

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So the option is b) sp3 and sp only

viswanath

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20 Oct 2007 22:04:25 IST

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ans is sp3 and sp

i ve got a simple technique
count the number of linkages to carbon ( a double bond or a triple bond is considered as a single linkage). if the number of linkages to carbon is 2 then hyb is sp,
if its 3 then sp2, if its 4 then sp3

in the given compound, the C atoms in the end have got 4 linkages each (3 with H and 1 with C). so its hyb is sp3
the C atoms in the middle have got 2 linkages each (1 with end carbon and 1with the other carbon). so its hyb is sp

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arun-rashi

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20 Oct 2007 23:41:31 IST

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to find out the hybridisation of any species use formula ,steric number =no.of sigma bond +lone pair if it is 2 hyb is sp,3 sp2,4 sp3,5sp3d ,6sp3d2 ,7sp3d3.if there is alkane it is sp3 if there is triply bonded alkyne hyb is sp so in this question correct option is b

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