IIT JEE , AIEEE Forum - Chemistry , Organic Chemistry

srujana

Please give the reaction mechanism for the following reaction:

        H₂C-COONa                     (Kolbe's electrolysis)               CH₂
   2        ||                + 2H₂O --------------------------------->           ||
        H₂C-COONa                                                               CH₂

madhusudan.chavan

Double bond shown in reactant molecule is not required. Sosium succinate on Kolbe's electrolysis would give ethene.The mechanism is as follows:

NaO¾C(=O)¾CH₂¾CH₂¾C(=O)¾ONa ®

.. ..

^- :O¾C(=O)¾CH₂¾CH₂¾C(=O)¾O: ^- ®

.. ..

. .

:O¾C(=O)¾CH₂¾CH₂¾C(=O)¾O: + 2 e ^-

.. ..

Free radical

® 2 CO₂ + ^.CH₂¾CH₂^.

Free radical

®CH₂=CH₂

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