:CCl2 > :CBr2 > :CH2 > :CF2
WHAT HAPPENS:
This order is so because, :CF2 is relatively very stable due to back bonding.
comparing the left 3 carbenes.
the extent of back bonding is very poor, due to high energy difference in orbitals of the overlapping orbitals (:CH2 doesn't do back bonding)
therefore we come to know that Cl and Br impart unstability to the molecule, whereas H doesn't do anything to the carbene
therefore :CH2 is more stable than :CCl2 and :CBr2
so now we consider Inductive effect, which is certainly more for Cl and therefore :CCl2 is less stable than :CBr2.
hence the final order is:
(reactivity)
:CCl2 > :CBr2 > :CH2 > :CF2