it suppeorts Sn1 due to high steric hindrance.
tellme whether i am correct or not?
reply is must.
The substrate is secondary. The base is strong, notice the inductive effects of the alkyl groups connected to O--
There is no stabilising factor for the negative charge. Thus the base is strong. If the base is strong, elimination is favoured on the secondary substrate. Thus E2 will occur. (Antiperiplanar conformation of H and the leaving group, Br, support E2)
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