physics chemistry maths science forums
become expert I help I sign up I login
refer a friend - earn nickels!!   
 advanced
 
Home
Ask & Discuss Questions
Study Material
Experts Zone
Hang Out!

Ask & Discuss Questions with Community & Experts

Moderation Team
   advanced
Ask iit jee aieee pet cbse icse state board community Community Discussion Question: The hydrolysis of Ester is called PSendo first order reaction.
Forum Index -> Organic Chemistry like the article? email it to a friend.  
Author Message
m.das (0)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [0 rates]

m.das's Avatar

total posts: 6    
offline Offline
Why it is called so?
    
polymath (143)

Hot goIITian

Olaaa!! Perrrfect answer. 23  [37 rates]

polymath's Avatar

total posts: 148    
offline Offline
its psuedo first order with respect to water  bcoz although its actually second order , but since water concentration remains almost unchanged we write a new rate constant assumin water concentration is constant. Not only this all solvolysis have psuedo order with respect to the solvent.
 
 
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
nivedh_89 (4457)

Blazing goIITian

Olaaa!! Perrrfect answer. 811  bad job dude!! I dont approve of this answer! 1  [1014 rates]

nivedh_89's Avatar

total posts: 1217    
offline Offline

Pseudo First Order Reaction


A
and B react to produce P:



If the initial concentration of the reactant A is much larger than the concentration of B, the concentration of A will not change appreciably during the course of the reaction The concentration of the reactant in excess will remain almost constant. Thus the rate's dependence on B can be isolated and the rate law can be written


Equation (1) represents the differential form of the rate law. Integration of this equation and evaluation of the integration constant C produces the corresponding integrated law.

Substituting [B] = c into equation (1) yields:

Integrating equation (2) gives:
The constant of integration C can be evaluated by using boundary conditions. At t = 0 the concentration of B is c0.

Therefore
Accordingly is obtained:

If the decrease in concentration of B is followed by photometric measurement the Beer' Law must be taken into account.

Combining equation (4) and Beer' Law

A = absorbance, e = molar absorbtivity with units of L · mol -1 cm -1
c = concentration of the compound in solution, expressed in mol · L -1
P0= radiant power for radiation entering; P= radiant power for radiation leaving


gives the relationship between k' and lnA:



One needs only monitor the relative concentration of B as a function of time to obtain the pseudo-first order rate constant k'. The value of k' can then be divided by the known, constant concentration of the excess compound to obtain the true constant second order k:


The pseudo-first order rate constant k' can be also determined from the half-life t1/2.


The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....

the PAIN or the PERSON...!!!
 this reply: 15 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Organic Chemistry
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya