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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Feb 2008 13:43:27 IST
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WATS D PRODCT ON REACTN OF CH3COCH2COOH WID NaBH4 AND LiAlH4?????PL XPLAIN............
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nabh4 will only reduce keto grp,,,,,,,,,,,,,bt lialh4 will reduce both carbonyl as well as keto grp.......dis is bcoz lialh4 is strong reducin agnt...............
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Feb 2008 17:42:48 IST
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baba is correct....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Feb 2008 22:10:50 IST
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very apyly answered..........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Feb 2008 22:26:49 IST
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@santosh..........
YES , NABH4 OR LIALH4 IS GOOD ENOUGH TO REDUCE KETONIC GROUP......... BUT ONLY LIALH4 WILL BE ABLE TO REDUCE CARBOXYLIC ACID........OR ANY OTHER CARBONYL GROUP for that matter....
the product in both cases will be an ALCOHOL..............
SO THE ANSWER WOULD BE........ A DIALCOHOL...........
OH / CH3 - CH - CH2 - CH2-OH.......
BUTAN -1,3 - DIOL.........
CORRECT ME IF I'M WRONG
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" the only thing thats always constant in this world , is change itself.....
so it is better to adapt to the situation or life makes you adapt to it (painfully)..."
- Kundan a.k.a Juan dankh......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2008 21:54:29 IST
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d answer matchd wid bat of baba.........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2008 22:46:28 IST
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CH3COCH2COOH +LiALH4=CH3COCH2CH2OH + H2O
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