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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 10:28:16 IST
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what is hoffmann elimination
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 10:41:41 IST
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Quarternary ammonium hailde in presence of moist Ag2O -------------> quuraternary ammonium hydroxide which on heating undergoes elimination to give an alkene along with water
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 11:15:03 IST
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generally, the product is anti-markonikov
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 18:52:43 IST
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http://en.wikipedia.org/wiki/Hofmann_elimination see this. you may get cleared. plz rate this yaar...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 19:07:10 IST
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generally the elimination follows saytzeff rule [the more substituted an alkene, the easier it is formed] however if the attacking base is tertiary and has bulky groups present on it, to minimize stric hindrance , the less substituted alkene will be formed. [think about the mechanism and you will understand why] this is your hoffmann elimination.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 19:12:46 IST
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when an amine is heated ch3I (in excess) and then followed by Ag2O and water in peresence of heat we get quartenery ammonium salt which on further rex'n gives alkene by anti mark rule
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