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Organic Chemistry
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Cool gay
Blazing goIITian

Joined: 13 Aug 2007
Posts: 687
30 Jun 2008 19:11:00 IST
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6th position par lagega ring ke....matlabb uppar se ring ke double bond ke saath wale right carbon par.. :D :D ..haina!!
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30 Jun 2008 19:21:29 IST
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halogenation occurs by the formation of cyclic intermediate, halonium ion(in solution) , the mechanism may be cald as SN2 having sn1 character... as far as i can remember crowding will be the deciding factor...isliye neeche wala double bond will break....
30 Jun 2008 20:51:29 IST
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cycloakanes and cykloalkenes both undergo halogenation reactions...........so it depend on the conditions..............
first case
if halogens -----uv radiations// then mechanism will proceed by free radical mechanism and the most stable intermediate(radical)will be formed which is the next one to the top double bond and to that halogen radical will be attached to that intermediate........hp...u.got it
second case only halogens then
double bond will break and the mechanism is easy.......(stated by few above)..............lower double bond will break.........
correct if am wrong
30 Jun 2008 21:07:39 IST
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dekho koi bond break nahi karega!!
as holagen will act as a electophile...n ch3 is o/p director..and also due to steric hinderance...halogen will be attatched 2 the para position wid respect 2 ch3.....i mean it will be the major product....the only bond which will break will be c-h bond...got it!!:)
30 Jun 2008 21:46:42 IST
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Which halogenation is this??
Cl2 + AlCl3 OR Cl2 + hv??
If it is Cl2 + AlCl3, then it is EAS and will occur at O/P position(I hope U understand which positions are like O/P positions in this compound).
If it is halogenation in presence of light, then it wud occur at alkane part and the reactivity can be found easily by the reactivity ratios of halogen with respecitve positions(i.e., primary, secondary, tertiary) in alkane.
Cl2 + AlCl3 OR Cl2 + hv??
If it is Cl2 + AlCl3, then it is EAS and will occur at O/P position(I hope U understand which positions are like O/P positions in this compound).
If it is halogenation in presence of light, then it wud occur at alkane part and the reactivity can be found easily by the reactivity ratios of halogen with respecitve positions(i.e., primary, secondary, tertiary) in alkane.
1 Jul 2008 09:38:28 IST
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my answer is correct..i suppose hez asking abt the halogenation which proceeds via free radical intermediate...please see the first reply of this post :D :D....and those who are talking of double bond..in most of the buks, case of bromine is given ....no there is no point of thinking in that direction












