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Physical Chemistry

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Joined:	6 Feb 2007
Post:	101

31 Mar 2007 19:20:08 IST

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533

30g

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30g of Mg and 30g of O2 are reacted and th residual mixture contains

a)60g of MgO only

b)40g of MgO and 20g of O2

c)45g of MgO and 15g of O2

d)50g of MgO and 10g of O2

Comments (2)

Bipin Dubey

Forum Expert

Joined: 23 Jan 2007

Posts: 7958

31 Mar 2007 21:58:53 IST

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Mg + (1/2)O₂

MgO

1 mole of Mg requires 0.5 mole of O₂ for oxidation.

Moles of Mg = 30/24

Moles of O₂ = 30/32

Moles of O₂ required = (1/2)(Moles of Mg) = 30/48

Hence moles of O₂ left = 30/32 - 30/48 = 5/16 = 10 g of O₂

Moles of MgO formed = 30/24 = (30/24)(40) g = 50 g

deepti hari

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Joined: 31 Mar 2007

Posts: 24

31 Mar 2007 22:18:06 IST

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i totally agree to the solution given by expert

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