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Blazing goIITian

Joined:	24 Sep 2008
Post:	1694

8 Apr 2009 00:23:55 IST

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579

A GOOD QUESTION ~ HAVE A LOOK ~

None

A GOOD QUESTION ~ HAVE A LOOK ~

FIND THE SOLUBILITY OF Mg(OH)₂ (K_sp = 10^-12 ) IN A SOLUTION OF pH VALUE 12 ???

A) 10^-8

B)10^-6

C)10^-5

D)10^-10

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Comments (8)

aNdRoMeDa

Blazing goIITian

Joined: 10 Sep 2007

Posts: 1319

8 Apr 2009 00:27:59 IST

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niche wali post dekho

aNdRoMeDa

Blazing goIITian

Joined: 10 Sep 2007

Posts: 1319

8 Apr 2009 00:31:02 IST

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JPS

Blazing goIITian

Joined: 21 Nov 2008

Posts: 1020

8 Apr 2009 00:31:53 IST

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is the answer 10^-10 ???

pranav agrawal

Blazing goIITian

Joined: 24 Sep 2008

Posts: 1694

8 Apr 2009 00:33:02 IST

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its the same method i did and same answer i got, but "luckily" no option is matching ~~~~~~ :D

pranav agrawal

Blazing goIITian

Joined: 24 Sep 2008

Posts: 1694

8 Apr 2009 00:34:22 IST

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the answer says 10 ^ -8 !!!!!!!! i m really shocked ~~~~ :(

aNdRoMeDa

Blazing goIITian

Joined: 10 Sep 2007

Posts: 1319

8 Apr 2009 00:39:33 IST

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haan aa toh gaya dear

we get

.25 *10^-8

n solubility we measure in small nos n nt 25 n so....... so tahts d answer

posted d sol bove :)

JPS

Blazing goIITian

Joined: 21 Nov 2008

Posts: 1020

8 Apr 2009 00:42:22 IST

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ya sorry...it is 10^-8.....[Ba2+] = S' , [OH-] = S' + 10^-2

now apply Ksp = (2S' + 10-2)2 (S').......omit the S2 and S3 terms as they are very small. u will get 10^-8

Prakhar Banga

Blazing goIITian

Joined: 20 Dec 2008

Posts: 599

8 Apr 2009 10:17:59 IST

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Mg(OH)2 = Mg2+ + 2OH-

[OH-] = 10^-2 (pOH = 2)

[Mg2+] = s

[Mg2+] [OH-]^2 = 10^-12

[Mg2+](10^-2)^2 = 10^-12

So s = 10^-8.

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