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Physical Chemistry

Scorching goIITian

 Joined: 1 Feb 2007 Post: 297
3 Feb 2007 22:17:01 IST
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6
937
a problem in chemical equilibrium.....please solve it
Engineering Entrance , Medical Entrance , NEET , JEE Main , AIIMS , JEE Main & Advanced , Chemistry , Physical Chemistry

the ammonia in equilibrium with nitrogen-hydrogen mixturein the ratio 1:3 at 673K and a pressure of 4*106Nm-2 is 20% by volume. calculate kp-(equilibrium constant in terms
of partial pressure)

Blazing goIITian

Joined: 3 Feb 2007
Posts: 1200
3 Feb 2007 23:47:06 IST
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is the answer 6.63*10-5

Scorching goIITian

Joined: 1 Feb 2007
Posts: 297
4 Feb 2007 10:28:59 IST
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hi aatish,
please tell me how you did it.........i am sorry the answer given here is

5.789*10-14 N-2 m4

Blazing goIITian

Joined: 5 Jan 2007
Posts: 378
4 Feb 2007 15:40:21 IST
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intially let the no. of moles of N2 & H2 be 1 & 3 respectively
N2 +3H2 --> 2NH3
initially                   1      3           0
equi.                  1-x       3-3x       2x
% by vol. of gas =% by mole

2x/(4-2x)=0.2
x=1/3
mole fraction of H2=(3-3x)/(4-2x)=0.6
mole fraction of N2=(1-x)/(4-2x)=0.2
kp= ((mole fraction of NH3*totol pressure)^2)/((mol frac of

N2 *total pressure)*(mol frac of H2 *total press)^3)

=5.789*10^(-14)

Cool goIITian

Joined: 3 Feb 2007
Posts: 69
5 Feb 2007 21:24:18 IST
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Hey sneha how did u get that step 2x/4-2x, it should be 2x/4-4x isnt it I think the anser is also quite wrong

Blazing goIITian

Joined: 3 Feb 2007
Posts: 1200
6 Feb 2007 19:39:37 IST
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Hey 12345 !! 2x/4-2x is the mole fraction for ammonia

ie Mole fraction = No. of moles / Total no. of moles

well done sneha

Forum Expert
Joined: 19 Oct 2006
Posts: 1057
7 Feb 2007 08:31:30 IST
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N2 +3H2 gives 2NH3 tatal p is 4 *10 to power 6,1-x  3-3x gives 2x  ,Kp is cal by ratio of partial pressure which is mole frection *tatal pressure.total moles is 4-2x at equilibrium given volume percentage which is taken as mole per. beca P  and T constent2x /4-2x =20/100 get x from here and calculate Kp.

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