The pressure exerted by 12g of an ideal gas at temperature t degrees C,in a vessel of volume V litre is 1 atm.when temperature is increased by 10 degrees at same volume,pressure increases by 10%.Calculate t and V(molecular wt. of gas=120).

For ideal gas -

             P₁ / T₁ = P₂/T₂

     --> P₁/P₂ = T₁/T₂

     Now , P₂ = 10%P₁ + P₁

     -->   P₂ = 11/10 P₁

   And, T₂= T₁+10

substituting    10 P₁ / 11 P₁ = T₁ / T₁ + 10

----> 10(T₁+10) = 11 T₁

---->T₁ = 100K

By substituting  T= 100K , P = 1 atm , n=12/120 mol and R = 0.0821 L atm K^-1 mol^-1  in PV=nRT ,

V=0.821 L