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Bhargav  sunny's Avatar
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8 May 2009 20:12:01 IST
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An alloy AB has NaCl like structure,and A occupies corners of cube.If all atoms of the face centres
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An alloy AB has NaCl like structure,and A occupies corners of cube.If all atoms of the face centres and bodycentre are removed,the composition(new formula of compound) is??????????


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Bhargav  sunny's Avatar

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22 May 2009 08:39:22 IST
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 can anyone solve this pls................

Sujit's Avatar

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22 May 2009 08:49:20 IST
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B3A

Bhargav  sunny's Avatar

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22 May 2009 08:51:04 IST
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 i need the explanation yar..........

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22 May 2009 08:54:02 IST
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is my answer correct
yeah...'s Avatar

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22 May 2009 08:54:36 IST
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in dis nacl = FCCas usual formula is AB3SO. a : b = 1/3dus , d given solid has AB.now face centres r removed ]derefore .. formaula wil be A1/3B = AB3
Bhargav  sunny's Avatar

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22 May 2009 08:54:59 IST
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 i dun remember the answer.........

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22 May 2009 08:55:41 IST
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in dis nacl = FCC

                          as usual formula is ABso a : b = 1/3dus ,

d given solid has AB       .now face centres r removed       derefore .. formaula wil be

A1/3B = AB3

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22 May 2009 08:55:53 IST
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@shailesh as mentioned in the ques...A is at corners so A shud be in FCC so the formula is B3A
Bhargav  sunny's Avatar

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22 May 2009 08:56:23 IST
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 pls sailesh.........

ur answer is not clear

pls make it clear

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22 May 2009 09:00:09 IST
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nacl structure is FCC .. nd sujit i din get u
Sujit's Avatar

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22 May 2009 09:04:13 IST
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i mean in NaCl...CL is at the corners so in this case A shud be the anion
Bhargav  sunny's Avatar

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22 May 2009 09:04:17 IST
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 thanq sailesh.........

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22 May 2009 09:05:55 IST
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k ... my answer was same but i have written dat in opposite manner
Sujit's Avatar

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22 May 2009 09:11:16 IST
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ya dat only i meant



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