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Blazing goIITian

Joined:	25 Oct 2008
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27 Feb 2009 12:23:15 IST

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An aq. solution contains5% by mass of urea & 10 % by mass of glucose . If molal depression constant

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An aq. solution contains5% by mass of urea & 10 % by mass of glucose . If molal depression constant of water is 1.86 K Kg / mol . Calculate freezing point.

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sneha

Blazing goIITian

Joined: 17 Mar 2008

Posts: 1243

27 Feb 2009 12:29:52 IST

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let total mass of solution be 100g.then mass of urea = 5

then moles of urea = 5/60 =1/12

similarly mass of glucose = 10

hence moles of it = 10/180 = 1/18

therefore total moles = 5/36

hence molality ={(5/36)}*1000/85 = 0.36

hence depreesion in f.p. = 1.86 * 0.36 =0.68

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