IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

lovegirl

hello everyone
here is my question
the molality of 1 m solution of sodium nitrate is 0.858 mol/kg. determine the density of the solution. how much BaCl₂ would be needed to make 250 ml of a solution having same concentration of Cl^- as the one containing 3.78g of NaCl per100 ml?
actually i know how to do this question but i m not getting the correct answer so plz help me in this question
thanx

frenied

since it is not mentioned wat the solvent is we take it to be water
now when weight of solution is 1kg wt.of NaNO3=0.858*85(mol.wt.)
wt.of water=1000-wt.of NaNO3=volume of water(density=1)
density=0.858*85/1000-wt.of NaNO3
for second question let volume be v and then equate molarities of Cl ions.remember 1 mol of BaCl2 will give 2 mol.of Cl ions.so if x moles of Bacl2 are taken moles of Cl will be=2x.

frenied

since it is not mentioned wat the solvent is we take it to be water
now when weight of solution is 1kg wt.of NaNO3=0.858*85(mol.wt.)
wt.of water=1000-wt.of NaNO3=volume of water(density=1)
density=0.858*85/1000-wt.of NaNO3
for second question let volume be v and then equate molarities of Cl ions.remember 1 mol of BaCl2 will give 2 mol.of Cl ions.so if x moles of Bacl2 are taken moles of Cl will be=2x.see if this helps if not just post a message here.

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