IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

Mandy_12_91

Decreasing order for NO2+,NO2-,NO3-

karthik2007

Hint: Calculate the Bond order for each of the molecules. Greater the bond order, small the bond length.

No of electrons in O and N are 8 and 7 respectively, moreover, account for the negative and positive charges properly.

Mandy_12_91

But bond order can be decided only for diatomic molecules, triatomic and quadatomic ke liye how do we find out?

drish

bond order -in decr. order

NO₃^--> NO₂^-- > NO₂⁺

^{HOPE I M CORRECT .}

ananth_patri

the same way as done for molecules whose no. of e is more than 14.....just cal the tot no of e and get bond order....higher the BO more stable implies less bond length as posted by karthik..

drish

and what is the ans.

Mandy_12_91

Ans is NO3->NO2->NO2+

Mandy_12_91

But that is precisely what my doubt is ........how exactly do u calculate B.O. for more than 14 electrons>?

abrambenny

U use the energy order of the species with fourteen electrns

Mandy_12_91

abrambenny

MO theory.

Mandy_12_91

Solve and show naaaaaaaa.........i know its MO

abrambenny

@Mandy
Dude...hand it to to... I've ransacked half of the net with few results...

Can someone pls give the energy level for the 3rd shell in the MO theory?

@Karthik...pls expln dude..

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